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Q) what is the output of the fallowing program ?


//one.java
class  output
{
    public static void main( String args[])
  {
                float a=43.80;
                System.out.println(a);
  }
}

A)
In the above program there is Syntactical error. If we use a decimal literal in a java application (here it is “43.80”), java compiler thread by default as double type. Therefore “loss of precision “error is reported.
-> to fix the problem we have to append    “ f ”/” F ”  to the decimal literal to indicate that it is a single precision literal. Or change the data type as “double”. F float a=43.80f; or float a=43.80f;
Or double a=43.80;
Note: byte , short , int and long represent numerical integer (non decimal) data types.


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